TNPSC GROUP 2 MATHS QUESTIONS WITH ANSWERS
1. The circle graph given here shows the spending of a country on various sports during a particular year. Study the graph and answer the question.
What percentage of the total spending is spent on Tennis?
A. 12.5%
B. 22.5%
C.25%
D.45%
ANS: A
EXPLANATION:
(45/360)×100=12.5%
2. Malini deposited Rs.7000/- with a finance company for 3 years at an interest of 15% per annum. What is the compound interest and the amount that Malini will get after 3 years?
A. C.I – Rs.3246, amount – Rs.13246
B. C.I – Rs.3646, amount – Rs.10646
C. C.I – Rs.6436, amount – Rs.16046
D. C.I – Rs.4636, amount – Rs.14636
ANS: B
EXPLANATION:
Amount= p×(1+r/100)n
=7000×(1+15/100)3
=7000×(115/100)3
=7000×(23/20)3
=10646
C.I=10646-7000=3646
3. The average salary of all workers in the factory is Rs.60. The average of salary of 12 officers is Rs.400. The average salary of rest is Rs.56. Find the total no of workers in the factory.
A. 1116
B. 1032
C. 1212
D. 1132
ANS: B
EXPLANATION:
12×400+X×56 = (12+X)×60
4800+56X = 720+60X
4X = 4080
X = 1020
Total no of workers = 12+X=12+1020=1032
4. The sides of a triangle are in the ration ½: 1/3: 1/4 and its perimeter is 104 cm. The length of longest side is
A. 52 cm
B. 48 cm
C. 32 cm
D. 26 cm
ANS: B
EXPLANATION:
LCM of 2,3,4 = 12
Therefore ½:1/3:1/4 = 6/12:4/12:3/12 = 6:4:3
6x+4x+3x = 104
13x = 104
x = 8
Longest side = 6x=48
5. If A’s salary is 20% less than B’s salary, by how much percent B’s salary more than A’s?
A. 24%
B. 25%
C. 20%
D. 22%
ANS: B
EXPLANATION:
[20/(100-20)] × 100 =[ 20/80]×100=25%
6. The volume of a cube is 125 cm3. The surface area of the cube is
A. 625 cm2
B. 125 cm2
C. 150 cm2
D. 100 cm2
ANS: C
EXPLANATION:
a3=125
a=5
Surface area = 6a2=6×25=150cm2
7. If 50% of (x-y)=30% of (x+y) then what percent of x is y?
A. 25%
B. 50%
C. 75%
D. 100%
ANS: A
EXPLANATION:
50/100 (X-Y) = 30/100 (X+Y)
1/2 (X-Y) = 3/10 (X+Y)
½ X - 3/10 X = 3/10 Y + 1/2 Y
2/10 X = 8/10 Y
Y = ¼ X
¼= 25%
8. 30 percent of a number is 15 less than 3/5th of a number. What is the number?
A. 48
B. 52
C. 50
D. 70
ANS: C
EXPLANATION:
30/100 X = 3/5 X – 15
3/10 X – 3/5 X = 15
3/10 X = 15
X = 50
9. The least number which when increased by 1 is divisible by 12,18,24,32 is
A. 278
B. 288
C. 287
D. 279
ANS: C
EXPLANATION:
Required number = [L.C.M of 12, 18, 24, 32] – 1
= 288 -1
= 287
10. The missing term in the series 9, 225, 16, 196, 25, 169, ___, 144
A. 81
B. 121
C. 36
D. 49
ANS: C
EXPLANATION:
9, 225, 16, 196, 25, 169, ___, 144
32, 225, 42, 196, 52,169, 62, 144
62 = 36
10. Find x in 4x × 642x = 16x+5
A. 1
B. 5
C. 4
D. 2
ANS: D
EXPLANATION:
4x × (43)2x = (42) x+5
4x × 46x = 42x+10
4x+6x = 42x+10
x + 6x = 2x+10
5x = 10
x=2
11. At simple interest Rs. 1000 becomes Rs. 1150 in 3 years. If the interest rate is increased by 3% then the total amount is
A. 1400
B. 1300
C. 1140
D. 1240
ANS: D
EXPLANATION:
S.I = 1150 – 1000 = 150
PNR/100 = 150
(1000×3×R) /100= 150
R = 5
R is increased by 3%, new R = 5+3 = 8%
New S.I = (1000×3×8)/100 = 240
Amount = 1240
12. If 7 spiders make 7 webs in 7 days, then 1 spider will make 1 web in how many days?
A. 1
B. 7/2
C. 7
D. 49
ANS: C
EXPLANATION:
SPIDERS
|
DAYS
|
WEBS
|
7
|
7
|
7
|
7
|
1
|
1
|
1
|
1
|
1/7
|
Therefore it will take 7 days.
13. The following table gives the life time of 500 CFL lamps:
Life time (months)
|
9
|
10
|
11
|
12
|
13
|
14
|
More than 14
|
Total
|
Number of lamps
|
26
|
71
|
82
|
102
|
89
|
77
|
53
|
500
|
A bulb is selected at random. The probability that the life time of the selected bulbatmost 11 months is given by
A. 82/500
B. 179/500
C. 97/500
D. 268/500
ANS: B
EXPLANATION:
(26+71+82)/500 = 179/500
14. Find the missing term in the diagram
4
|
5
|
10
|
8
|
12
|
8
| ||
20
|
9
|
80
|
18
|
?
|
20
|
A. 25
B. 30
C. 96
D. none of these
ANS: C
EXPLANATION:
4×5 = 20
10×8 = 80
12 × 8 = 96
15. The sum of three prime numbers is 101. The difference of two of them is 24. What are the numbers?
A. 5, 59, 37
B. 41, 53, 7
C. 11, 37, 53
D. 3, 61, 37
ANS: D
EXPLANATION:
Clue: go with options.
3+61+37 = 101
61 – 37 = 24
16. If 18% of the total number of oranges in a basket is 36. Then the total number of oranges is
A. 100
B. 150
C. 200
D. 300
ANS: C
EXPLANATION:
(36/18)×100 = 200
17. The ratio of the prices of two cows was 23:16. Two years later the price of the first cow rises by Rs.477 and that of the second by 10% and the ratio of their pries become 20:11. Find the original prices
A. Rs. 1219, Rs. 848
B. Rs. 1218, Rs. 848
C. Rs. 1210, Rs. 850
D. Rs. 1219, Rs. 840
ANS: A
EXPLANATION:
(23X+477) / [16X + (10/100)] × 16X = 20/11
(23X+477) × 11 = 20 × [16X + (16/10) X]
253X+477×11 = 320X + 32 X
253X+477×11 = 352X
99X = 477×11
X= 477× 11/99
X = 53
23X = 23×53 = 1219
16X = 16×53 = 848
18. A ladder of 25 ft length reaches a window which is 24 ft above the ground level on one side of the street. Keeping its foot at the same point the ladder is turned the other side of the street and now reaches a window of 7 ft high. Then width of the street
A. 30
B. 32
C. 29
D. 31
ANS: D
EXPLANATION:
According to Pythagoras theorem
a = root of (252- 242)= root of (49)=7
b = root of (252- 72)= root of (576)=24
|
Width of the street a + b=7+24 = 31
<---------Width------------>
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